Physics, asked by shivadathann7326, 1 year ago

If the pressure of a gas is doubled at constant temperature then the mean square velocity will become

Answers

Answered by Wafabhatt
13

The root mean square velocity V(r.m.s) = √[ 3*R*T/M]

where, T= absolute temperature

R = universal constant

M= molar mass of the gas molecules

If the gas is considered to be an ideal case equation than,

P*V= R*T

so the modified V(r.m.s) value is;

V(r.m.s) = √[ 3*P*V/M]

where. P = pressure of the ideal gas

V= volume of the ideal gas

So when the Pressure of gas is doubled, the volume is halfed but the root mean square velocity remains unchanged.

Answered by Yeshwanth1245
4

Answer:

The root mean square velocity V(r.m.s) = √[ 3*R*T/M]

where, T= absolute temperature

R = universal constant

M= molar mass of the gas molecules

If the gas is considered to be an ideal case equation than,

P*V= R*T

so the modified V(r.m.s) value is;

V(r.m.s) = √[ 3*P*V/M]

where. P = pressure of the ideal gas

V= volume of the ideal gas

So when the Pressure of gas is doubled, the volume is halfed but the root mean square velocity remains unchanged.

Explanation:

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