If the pressure of a gas is doubled at constant temperature then the mean square velocity will become
Answers
The root mean square velocity V(r.m.s) = √[ 3*R*T/M]
where, T= absolute temperature
R = universal constant
M= molar mass of the gas molecules
If the gas is considered to be an ideal case equation than,
P*V= R*T
so the modified V(r.m.s) value is;
V(r.m.s) = √[ 3*P*V/M]
where. P = pressure of the ideal gas
V= volume of the ideal gas
So when the Pressure of gas is doubled, the volume is halfed but the root mean square velocity remains unchanged.
Answer:
The root mean square velocity V(r.m.s) = √[ 3*R*T/M]
where, T= absolute temperature
R = universal constant
M= molar mass of the gas molecules
If the gas is considered to be an ideal case equation than,
P*V= R*T
so the modified V(r.m.s) value is;
V(r.m.s) = √[ 3*P*V/M]
where. P = pressure of the ideal gas
V= volume of the ideal gas
So when the Pressure of gas is doubled, the volume is halfed but the root mean square velocity remains unchanged.
Explanation: