If the pressure of N2/H2 mixture in a closed apparatus is 100 atm and 20% of the mixture reacts,then the pressure at same temperature would be?
Answers
Answered by
2
Answer:
20% mixture reacts to form 10%NH3 , Thus 80% mixture and 10%NH3 left or total pressure left =90atm since 100% mixture has 100at
Answered by
2
Answer:
90 atm
Explanation:
N₂ + 3H₂ ⇒ 2NH₃
4 moles of reactant react to give 2 moles of NH₃
Thus 20% mixture gives 10% NH₃
Thus remaining amount of mixture = 100% - 20% = 80%
Total pressure is due to the individual partial pressures of mixture and NH₃
= 80% + 10% = 90%
Thus, 90% of 100 atm = 90 atm
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