if the pressure of the gas increases by keeping it's temperature constant, the RMS speed of the molecules of the gas
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Answered by
2
Answer:
330.33K= 57.33°C
Explanation:
RMS VELOCITY =√(3RT/M).
RMS VELOCITY AT NTP , V°=√(3RT°/M)
RMS AT TEMPATURE T, V=√(3RT/M).
SO V/V°=√[(3RT/M)÷(3RT°/M)] .
Therefore 1.1= √(T/T°)
So T/T° = 1.1^2=1.21
So T= 1.21 xT°= 1.21 x 273
= 330.33K= 57.33°C
Answered by
1
Answer:
if the temperature is increased the average speed and kinetic energy of the gas molecules increase.if the volume held constant the increased speed of the gas molecules results in more frequent and more forceful collisions with the walls of the container, therefore increasing the pressure.
Explanation:
hope it's helpful to you
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