Question

If the price of 12 shirts is ₹3600 2/5 and price of 6pants is 3000 3/4 the price of 4shirts and 4 pants ​

Answer 1

Explanation:

Let the price of one shirt be x,

and the price of one pant be y.

Then,

$12x = 3600 \times 2 \div 5$

and,

$6y = 3000 \times 3 \div 4$

Therefore,

x = (3600×2/5)/12

=> x = 120

and,

y=(3000×3/4)/4

=> y= 562.5

Therefore the cost of 4 pants and 4 shirts is

₹(4×120)+(4×562.5)

=₹480+2250

=₹2730