Question

if the price of 3 pens 2 pencils and 4 eraser is 92 and the price of 8 pencils and 16 eraser is 68 then the price of 24 pens is what​

Answer 1

Step-by-step explanation:

Let the price of one pen be x, one pencil be y and one eraser be z .

Therefore, 3x + 2y + 4z=92. ....(i)

also , 8y + 16z = 68 ....(ii)

Now, we multiply (i) by 4 and subtract it from (ii) :

4(3x + 2y + 4z) - (8y + 16z) = 4×92 - 68

=> 12x + 8y + 16z - 8y - 16z = 368-68

=> 12x = 300

=> x = 300 / 12

=> x = 25

Therefore , price of 1 pen = 25

so , price of 24 pens = 24×25 = 600 ( your answer. )

This sum involves the use of Simultaneous linear equation...

Thanks for asking the question...