Math, asked by sukumaran18, 8 months ago

If the price of a book is reduced
by Rs 5
R:s a a person can buy 5 more
books for Rs 300 . Find the original price
of the book.​

Answers

Answered by sumitrohilla40
0

Answer:

Let the prize of one book be Rs. x

let the no. of books be y

so total amount spent = xy

300 =xy

now changed price of book = Rs. (x -5)

no. of books bought = y + 5

so total amount spent = (x - 5)(y + 5)

300 = xy +5x -5y -25

325 = 300 + 5(x - y)

25 = 5(x - y)

x - y = 5

y = x - 5

now putting this in xy = 300

(x - 5)x = 300

x2 -5x - 300 = 0

x2 -20x + 15x -300 = 0

(x - 20) ( x + 15) = 0

x = 20 or x = -15

Price of book cannot be negative so x is not equal to -15

so actual cost of book is x= Rs. 20

Step-by-step explanation...

hope this answer helps you....

Answered by gundasuresh450
0
  • Let the original price = x

  • No.of books = y

  • Total price of books = xy =300

NOW:

  • Reduced price = (x-5)

  • No.of books bought = (y+5)

WE KNOW THAT:

PRICE = NO.OF BOOKS BOUGHT × REDUCED PRICE.

  • (x-5)(y+5)=300

  • x(y+5)-5(y+5) = 300

  • xy+5x-5y-25 = 300

  • xy+5x-5y = 300+25

  • xy+5x-5y = 325

  • xy+5(x-y) = 325

BUT XY=300:

  • 300+5(x-y) = 325

  • 5(x-y) = 325-300

  • 5(x-y) = 25

  • x-y = 25/5

  • x-y = 5

  • x = 5+y......1

PUT X VALUE IN XY=300:

  • xy = 300

  • (5+y)y = 300

  • y^2+5y-300 = 0

  • y^2+20y-15y-300 = 0

  • y(y+20)-15(y+20) = 0

  • y-15=0 , y+20=0

  • y=15 , y = -20

SINCE WE CANT TAKE NEGATIVE VALUE

THEREFORE y = 15

PUT Y VALUE IN THE EQUATION 1:

  • x = 5+y

  • x = 5+15

  • x = 20

Therefore,the original price of book = 20rs.

REDUCED ŔS.

  • x-5

  • 20-5

  • = 15rs

Therefore,reduced price = 15rs.

MARK AS BRANLIEST ANS. BROO..

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