Question

if the price of an article is increased by 10%.and after that decreased by another 10%.calculate the final price of the article.If the initial value of article is rs 100​

Answer 1

Answer:

10% of 100= 10

10+100=110

10% of 110 = 11

110-11=99

Answer 2

Value of article when increased 10% :

$\sf \dashrightarrow 100 + (10\% \: of \: 100)$

$\sf \dashrightarrow 100 + \bigg( \dfrac{10}{100} \times 100 \bigg)$

$\sf \dashrightarrow 100 + \bigg( \dfrac{1}{10} \times 100 \bigg)$

$\sf \dashrightarrow 100 + \bigg( \dfrac{1 \times 100}{10}$

$\sf \dashrightarrow 100 + \bigg( \dfrac{100}{10} \bigg)$

$\sf \dashrightarrow 100 + 10$

$\sf \dashrightarrow Rs.110$

Final price of the article

$\sf \dashrightarrow 110 - (10\% \: of 110)$

$\sf \dashrightarrow 110 - \bigg( \dfrac{10}{100} \times 110$

$\sf \dashrightarrow 110 - \bigg( \dfrac{1}{10} \times 110 \bigg)$

$\sf \dashrightarrow 110 - \bigg( \dfrac{1 \times 110}{10} \bigg)$

$\sf \dashrightarrow 110 - \bigg( \dfrac{110}{10} \bigg)$

$\sf \dashrightarrow 110 - 11$

$\sf \dashrightarrow Rs.99$