If the price of
Goat is 0.50Rs
Horse is 3Rs
Elephant is 10Rs
What will be the number of goats, horse and elephants such that total number of animals should be 100 and the price of the total animals should be also 100Rs
Answers
Given :
The price of goat = Rs 0.5
The price of horse = Rs 3
The price of elephant = Rs 10
Total number of animals = 100
To price of all animals = Rs 100
To Find :
Total number of goat
Total number of horse
Total number of elephant
Solution :
Let The number of goat = g
The number of horse = h
The number of elephant = e
∵ Total number of animals = 100
i.e g + h + e = 100 ..........1
Again
0.5 g + 3 h + 10 e = 100 ............2
Or, 0.5 g + 0.5 h + 0.5 e = 0.5 × 100
i.e 0.5 g + 0.5 h + 0.5 e = 50
So, ( 0.5 g + 3 h + 10 e ) - ( 0.5 g + 0.5 h + 0.5 e ) = 100 - 50
Or, 2.5 h + 9.5 e = 50
For h = 1
9.5 e = 50 - 2.5
9.5 e = 47.5
∴ e = = 5
So, Number of elephant = e =5
And number of horse = h = 1
Put h and e value in eq 1
i.e g + 1 + 5 = 100
Or, g = 100 - 6
∴ g = 94
So, number of goat = 94
Hence, The Total number of goat is 94
Total number of horse is 1
Total number of elephant is 5 Answer
The number of goats, horse and elephants are 94, 1, and 5 respectively.
Step-by-step explanation:
Let number of goats be x
Let number of horse be y
Let number of elephants be z
From question, the total number of animals is 100, thus,
x + y + z = 100 → (equation 1)
From question, the price of the total animals is also Rs. 100, thus,
0.5x + 3y + 10z = 100 → (equation 2)
From the question, two equations with three unknowns are formed. Thus, the equations have infinite number of solutions.
Now, on multiplying equation (1) with 0.5, we get,
0.5x + 0.5y + 0.5z = 50 → (equation 3)
On solving equation (2) and (3), we get,
2.5y + 9.5z = 50 → (equation 4)
Let's assume the value of y = 1, we get,
2.5 + 9.5z = 50
9.5z = 50 - 2.5
9.5z = 47.5
z = 47.5/9.5 = 5
Therefore, y = 1 and z = 5
On substituting value of y and z in equation (1), we get,
x + 1 + 5 = 100
x + 6 = 100
x = 100 - 6 = 94