Math, asked by manaselec, 1 month ago

If the price of joshon phone is 20%more than that of Franklin phone then by what percent is the frnklink phone less than of jashon phone?

Answers

Answered by Anonymous
0

Answer:

17%

Step-by-step explanation:

let price of Jason phone = j, Franklin phone =f

j = f+ 20%f

= 1.2f

f=1/1.2 j

=0.83 j

= j - 0.17j

= j - 17%j

f decreased by 17% of j

 \\  \\

Similar questions