If the price of pen decreases by 20%, then a man can buy 10 more pens for rs 100. what is the new price (in rs) of each pen?
Answers
Answered by
32
Let the number of pens brought originally be x and cost of each pen be y.
Therefor according to the question
x*y = 100 ............................(1)
and
(0.8*y)*(x + 10) = 100 .................(2)
by equation 2,
(0.8)*x*y + 8*y = 100
using equation 1,
(0.8)*(100) + 8*y = 100
8*y = 20
=> y = 2.5
Therefore the new price is (0.8)*y = 0.8 * 2.5 = 2
The answer is Rs.2
Therefor according to the question
x*y = 100 ............................(1)
and
(0.8*y)*(x + 10) = 100 .................(2)
by equation 2,
(0.8)*x*y + 8*y = 100
using equation 1,
(0.8)*(100) + 8*y = 100
8*y = 20
=> y = 2.5
Therefore the new price is (0.8)*y = 0.8 * 2.5 = 2
The answer is Rs.2
Answered by
9
Let the price of 1 pen initially be Rs. X
⇒ Number of pens he can buy now = 100/x
After 20% discount price of 1 pen = x(1 – 20/100) = 0.8x
⇒ Number of pens he can buy now = 100/0.8x
According to problem statement,
⇒ 100/0.8x – 100/x = 10 pens
⇒ (100/x) × 1/4 = 10
⇒ x = 2.5
∴ the new price is 2.5 × 0.8 = Rs. 2
⇒ Number of pens he can buy now = 100/x
After 20% discount price of 1 pen = x(1 – 20/100) = 0.8x
⇒ Number of pens he can buy now = 100/0.8x
According to problem statement,
⇒ 100/0.8x – 100/x = 10 pens
⇒ (100/x) × 1/4 = 10
⇒ x = 2.5
∴ the new price is 2.5 × 0.8 = Rs. 2
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