Question

if the prime factorisation of a natural number (n) is 2^3 × 3^2× 5^2 × 7 . how many consecutive zeroes will it have at end ? justify your answer​

Answer 1

Answer: two zeros

Step-by-step explanation:

2^2x5^2 = 10^2 = 100

i.e. the number is a multiple of 100 so it will have two zeroes at the end

Answer 2

Answer:

It will have 2 zeroes.

Step-by-step explanation:

Given :-

• 2³ × 3² × 5² × 7

To find :-

The number of zeroes.

Solution :-

First break the expression.

2³ × 3² × 5² × 7

= 2×2×2 × 3×3 × 5×5 × 7

= (5×2) × (5×2) × 2 × 3×3 × 7

= 10×10 × 2 × 3×3 × 7

= 100 × 2 × 3×3 × 7

Therefore, It will have 2 zeroes.

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