Math, asked by ARFrocks, 1 year ago

if the prime factorisation of a natural number (n) is 2^3 × 3^2× 5^2 × 7 . how many consecutive zeroes will it have at end ? justify your answer​

Answers

Answered by pavamuruganpbcfes
3

There will be 3 consecutive zeroes.

The trick is, find how many 2 and 5 are there, there are 3 pairs of 2 and 5 hence, 3 zeroes.

Hope this helps you friend

Thanks ✌️❤️


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