if the prime factorisation of a natural number (n) is 2^3 × 3^2× 5^2 × 7 . how many consecutive zeroes will it have at end ? justify your answer
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There will be 3 consecutive zeroes.
The trick is, find how many 2 and 5 are there, there are 3 pairs of 2 and 5 hence, 3 zeroes.
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