Question

if the prime factorisation of a natural number N is 2^4*3^4*5^3*7.Write the number of consecutive zeros in N
#pls fast#

Answer 1

♠Answer♠

There will be 3 consecutive Zeroes .

The Trick is , find how many 2 and 5 are there , there are 3 pairs of 2&5 hence , 3 zeroes .

#SupermanINFINITY

Answer 2

(2^4)*(3^3)*(5^3)*(7^2)
= (2)*[(2*5)^3]*(3^3)*(7^2)
= (2)*(10^3)*(3^3)*(7^2)
the will be 3 is concutive zero in n.