Question

if the prime factorisation of a natural number N is 2^4×3^4×5^3×7,write the number of consecutive zeros in N .

Answer 1

Answer:

There will be 3 consecutive zeroes in N.

Step-by-step explanation:

Given : If the prime factorization of a natural number N is $2^4\times3^4\times5^3\times7$

To find : Write the number of consecutive zeros in N?

Solution :

Prime factorization of a natural number N is

$2^4\times3^4\times5^3\times7$

The consecutive zeros are the power of multiple of 2 and 5

$3^4\times7\times2(2^3\times5^3)$

$3^4\times7\times2\times 10^3$

So, There will be 3 consecutive zeroes in N.

Answer 2

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