Question

If the prime factorisation of a natural number N is 2^4*3^4*5^3*7.write the number of consecutive zeros of N.

Answer 1

3 zeros.

$2^4 \times 3^4 \times 5^3 \times 7 \\ \\ = 2^3 \times 2 \times 5^3 \times 3^4 \times 7 \\ \\ = (2^3 \times 5^3) \times 3^4 \times 7 \\ \\ = 10^3 \times 3^4 \times 7$

∴ 3 consecutive zeros in N.

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