if the prime factorization of a natural number N is 2 into 2 into 2 into 3 into 3 into 5 into 5 into 7 write the number of consecutive zeros in n
Answers
Answered by
0
2×2×2×3×3×5×5×7=12600
So, the number of consecutive zeroes is only two(2).
Hope it helps
So, the number of consecutive zeroes is only two(2).
Hope it helps
Similar questions