Math, asked by Anonymous, 1 year ago

if the prime factorization of a natural number N is 2 into 2 into 2 into 3 into 3 into 5 into 5 into 7 write the number of consecutive zeros in n

Answers

Answered by Chitransh0709
0
2×2×2×3×3×5×5×7=12600
So, the number of consecutive zeroes is only two(2).
Hope it helps
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