Question

if the prime factorization of a natural number (n) is 23x 32x52x7 how many consecutive zeroes will it have at the end of it? Justify your answer

Answer 1

Answer:

4

Step-by-step explanation:

Answer 2

Answer:

23×32×52×7

$= {2}^{7} \times 7 \times 13 \times 23$

$= 267904$

here,

there are no zeroes at the end of the number

so the number of zeroes is 0