Question

If the prime factorization of a natural number n is $2^{3}* 3^{2}*5^{2}*7$, Write the number of consecutive zeros in n.

Answer 1

SOLUTION :  

GIVEN : Prime factorization of a natural number n is 2³ × 3² ×5² × 7

n =  2³ × 3² ×5² × 7

n = 8 × 9 × 25 × 7

n = 8 × 25 × 9 × 7

n = 200 × 63

n = 12600

Hence, the number of consecutive zeros in n are two (2).

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Answer 2

Answer:

Step-by-step explanation:

Given :-

Prime factorization of a natural number n is 2³ × 3² ×5² × 7.

To Find :-

Number of consecutive zeros in n.

Solution :-

⇒ n =  2³ × 3² × 5² × 7

⇒ n = 8 × 9 × 25 × 7

⇒ n = 8 × 25 × 9 × 7

⇒ n = 200 × 63

⇒ n = 12600

Hence, the number of consecutive zeros in n are two (2).