Question

if the principal is ₹48,000, time is 3 years and the simple interest is ₹420, then find the rate of interest...

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Answer 1

GIVEN :-

• Principal , P = Rs. 48000.
• Time , T = 3 years.
• Simple Interest , S.I = Rs. 420.

TO FIND :-

• Rate % , R = ?

SOLUTION :-

$\\ \red \bigstar \: \underline{ \boxed{\displaystyle \tt \: Rate \% = \dfrac{S.I \times 100}{P \times T}}}$

$\orange \bigstar \purple{ \displaystyle \: \tt \: \: Substitute \: all \: the \: given \: values \: }$

$: \implies \displaystyle \tt \: Rate \% = \dfrac{42 \cancel0 \times \cancel{100}}{48 \cancel{000} \times 3}$

$: \implies \displaystyle \tt \: Rate \% = \dfrac{42}{3 \times 48}$

$: \implies \displaystyle \tt \: Rate \% = \dfrac{42}{144}$

$\red \bigstar \: \underline{ \boxed{\displaystyle \tt \: Rate \% = 0.29 \: \%}}$

$\therefore \underline{ \displaystyle \tt \: Required \: Rate \: \% \: is \: 0.29\:. }$

ADDITIONAL INFORMATION :-

$\red{ \underline{\bf Some Formulae}} \\ \\ :\implies \quad \tt P = \dfrac{100 \times S.I}{R \times T} \\ \\ \\ : \implies \quad \tt T = \dfrac{100 \times S.I}{P \times R} \\ \\ \\ : \implies \quad \tt R = \dfrac{100 \times S.I}{P \times T} \\ \\ \\ : \implies \quad \tt A = P + S.I \\ \\ \\ : \implies \quad \tt S.I = \dfrac{P \times R \times T}{100}$

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow PRINCIPAL(p)= \₹ 48000$

$\sf\dashrightarrow TIME (t)= 3years$

$\sf\dashrightarrow SIMPLE\: INTEREST (S.I)= \₹ 420$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow RATE\:\%(percent)$

✯FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\: rate\% = \dfrac{ (S.I) \times 100}{ (principal) \times (time)} \:\: \star}}}$

$\large\underline\bold{SOLUTION}$

$\sf\therefore rate\% = \dfrac{ (S.I) \times 100}{ (principal) \times (time)}$

$\sf\dashrightarrow rate\%= \dfrac{ 420\: \times 100}{ 48000 \times 3}$

$\sf\implies \dfrac{ 420\: \times \cancel{100}}{ 480\:\times \cancel{100} \times 3}$

$\sf\implies \dfrac{420}{480 \times 3}$

$\sf\implies \dfrac{42\: \times \cancel{10}}{48\:\:\times \cancel{10} \times 3}$

$\sf\implies \dfrac{\cancel{42}}{ 48 \times \cancel{3}}$

$\sf\implies \dfrac{14}{48}$

$\sf\implies \cancel\dfrac{14}{48}$

$\sf\implies 0.297$

$\large{\boxed{\bf{ \star\:\: THE\:REQUIRED\:RATE\:\%= 0.297\:\: \star}}}$

$\large\underline\bold{THE\:REQUIRED\:RATE\:\%\:IS\:0.297}$

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