Question

if the principal is RS 1000 the rate of interest is 10% the duration is 6 yrs what would be the simple interest​

Answer 1

Given:

• Principal = Rs. 1000
• Rate = 10 %
• Time = 6 years

What To Find:

We have to find the simple interest.

Formula Needed:

$\it SI = \dfrac{P \times R \times T}{100}$

Where,

• SI = Simple Interest
• P = Principal
• R = Rate
• T = Time

Solution:

Using the formula,

$\sf \implies SI = \dfrac{P \times R \times T}{100}$

Substitute the values,

$\sf \implies SI = \dfrac{1000 \times 10 \times 6}{100}$

Cancel the zeros,

$\sf \implies SI = 10 \times 10 \times 6$

Multiply the values,

$\sf \implies SI = Rs. \: 600$

Final Answer:

∴ Thus, the SI of the follwing is Rs. 600.

Answer 2

Given:

Principal = Rs. 1000

Rate = 10 %

Time = 6 years

What To Find:

We have to find the simple interest.

Formula Needed:

$\it SI = \dfrac{P \times R \times T}{100}$

Where,

SI = Simple Interest

P = Principal

R = Rate

T = Time

Solution:

Using the formula,

$\sf \implies SI = \dfrac{P \times R \times T}{100}$

Substitute the values,

$\sf \implies SI = \dfrac{1000 \times 10 \times 6}{100}$

Cancel the zeros,

$\sf \implies SI = 10 \times 10 \times 6$

Multiply the values,

$\sf \implies SI = Rs. \: 600$

Final Answer:

∴ Thus, the SI of the follwing is Rs. 600.