Question

If the principal quantum number is n=4 then 1 = what

Answer 1

For n=4;l=0,1,2,3.

For n=4;l=0,1,2,3.N=1 present K-shell and the number of elements having K shell =2

For n=4;l=0,1,2,3.N=1 present K-shell and the number of elements having K shell =2N=2 present L shell and the number of element having L shell =8

For n=4;l=0,1,2,3.N=1 present K-shell and the number of elements having K shell =2N=2 present L shell and the number of element having L shell =8N=3 present M shell and the number of elements having M shell =18

For n=4;l=0,1,2,3.N=1 present K-shell and the number of elements having K shell =2N=2 present L shell and the number of element having L shell =8N=3 present M shell and the number of elements having M shell =18N=4 present N shell and the number of elements having N shell =32

For n=4;l=0,1,2,3.N=1 present K-shell and the number of elements having K shell =2N=2 present L shell and the number of element having L shell =8N=3 present M shell and the number of elements having M shell =18N=4 present N shell and the number of elements having N shell =32Total number =2+8+18+32=60

For n=4;l=0,1,2,3.N=1 present K-shell and hope it's helpful if it is then please mark me as brainliest