if the probability of 53 Fridays in a non leap year is x/3x+ 4 then X is
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Answer:
There are 365 days in a leap year =52 weeks + 1 day.
52 weeks have 52 Fridays.
So, the last 1 day can be any of the seven days of the week out of which only one day is Friday.
So, Probability that a non leap yeas has 53 Fridays=
Totalnumberofoutcomes
Numberoffavourableoutcomes
=
7
1
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