Question

If the probability of an event E happening is 0.023, then P( not E) =​

Answer 1

Answer:

P(notE)=0.977

Step-by-step explanation:

We know that

P(E)+P(notE)=1

=> P(notE)=1-P(E)

=>P(notE)= 1- 0.023

=0.977

=>P(notE)=0.977

Answer 2

If the probability of an event E happening is 0.023, then P( not E) is given as follows.

We know that

$P(A) + P(\bar {A}) = 1$

So, given,

P(A) = 0.023

we have,

$0.023 + P(\bar {A}) = 1$

$P(\bar {A}) = 1 - 0.023$

$\therefore P(\bar {A}) = 0.977$

OR,

0.023 = 23/1000

$P(A) + P(\bar {A}) = 1$

$\dfrac{23}{1000} + P(\bar {A}) = 1$

$P(\bar {A}) = 1 - \dfrac{23}{1000}$

$\therefore P(\bar {A}) = \dfrac{1000-23}{1000} = \dfrac{977}{1000}$

$\dfrac{977}{1000} = 0.977$