Question

if the probability of getting sum 7 or 10 on uppermost face when a pair of dice is thrown?
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Answer 1

Step-by-step explanation:

A pair of dice is rolled.

Total out comes = 36

(I) Sum of numbers on upper forces is greater then 7.

⇒sum=8,9,10,11 or 11

⇒ Possible out comes are :

(2,6),(3,5),(4,4),(5,3) and (6,2)→8

(3,6),(4,5),(5,4),(6,3)→9

(4,6),(5,5),(6,4)/(5,6),(6,5)→10/11

(6,6)→12

⇒ Favorable outcomes = 15

⇒ Probability = 3615=125

(II) sum = Perfect square = 4,9

⇒ Favorable are : (1,3),(2,2),(3,1),(3,6),(45),(5,4),(6,3)  Total = 7

⇒P=367

(III) Sum = 10

⇒ out comes are : (4,6),(5,5) and 6,4)

P=363=121