. If the probability of hitting a target by a shooter in any
shot is 1/3 , then the minimum no. of
independent shots at the target required by him so that
the probability of hitting the target atleast once is
greater than 5/6, is
(a) 6 (b) 3 ( c) 5(d) 4
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The probability of hitting the target at least once is greater than 5/6 is 5.
Step-by-step explanation:
Let the no. of attempts be = n
Probability of success = 1/3
Probability of failure = 2/3
Probability of success at least once = 1 - probability of no success
= 1 - nCn (2/3)^n
= 1 - ( 2/3)^n
Now
1 - ( 2/3) > 5/6
So n = 5
Thus the probability of hitting the target at least once is greater than 5/6 is 5.
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