Question

If the probability of hitting a target by a shooter, in any shot, is 1/3,
then the minimum number of independent shots at the target required by him so that the probability of hitting the target at least once is greater than 5/6, is :
(A) 3 (B) 6
(C) 5 (D) 4

Answer 1

Answer:

3

Step-by-step explanation:

1/3=2/6

2/6*3 =6/6

6/6>5/6