Question

if the probability of occurrence of an event E, P( E ) is 0.99, then what is the probability of not occurrence of event P ( not E ) ?

Answer 1

P(not E) =1-P(E)
=1-0.99
=0.01





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Answer 2

Answer-

The probability of not occurrence of event P(Not E) is 0.99

Solution-

E = event of occurrence

Given,

$P(E)=0.99$

If F is the event of not occurrence,then the probability of F will be,

$P(F)=P(Not\ E)=1-P(E)=1-0.99=0.01$

Then, probability of not occurrence of event F will be,

$P(Not\ F)=1-P(F)=1-0.01=0.99$

Therefore, the probability of not occurrence of event P(Not E) is 0.99