If the probability of winning a football match is 2/3 more than twice of probability of losing the match,find the probabilities of winning and losing the match.
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Answered by
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p=winning a football match
q=losing the match
Given__
P=2q+(2/3)
You know that
p+q=1
2q+(2/3)+q=1
3q=1-(2/3)
3q=1/3
q=1/9
p=1-q=1-(1/9)=8/9
Hence, p=8/9 and q=1/9
Answered by
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let prbability of loosing game be x
2/3+2x+x=1
2/3+3x=1
x=1/9
probability of winning game is 1-1/9=8/9
2/3+2x+x=1
2/3+3x=1
x=1/9
probability of winning game is 1-1/9=8/9
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