Question

if the probability of winning a game is 0.38.what is the probability of losing it?

Answer 1

Given:

We have the probability of winning a game is 0.38.

To Find:

We have to find the probability of losing the game?

Step-by-step explanation:

• The probability of any event is known as the possibility of occurring that event.
• we know the probability of an event is calculated by the number of favorable outcomes divided by the total number of terms.
• Now some properties of probability are
• 1) Probability of any event lies between the 0 and 1 it will never less then 0 and also not exceed 1.

• 2) Probability of occurring an event add to the probability of not occurring will always result to 1.
• We have given the probability of winning a game is 0.38
• Probability of occurring event is 0.38 which is written as P(E)=0.38

• We have to find the probability of not rain which is represented by $P(\bar E)$

• We know the probability of occurring and non-occuring is 1 which means

        $P(E)+P(\bar E)=1\\0.38+P(\bar E)=1\\\\P(\bar E)=1-0.38=0.62$

Hence, the Probability of losing the game is 0.62

Answer 2

Given:

The probability of winning a game is 0.38

To find:

The probability of losing the game

Solution:

The probability of losing the game is 0.62.

We can find the probability by following the given steps-

We know that when an event is sure to happen, its total probability is one.

So, the sum of the probability of winning the game and losing the game is 1.

Probability of winning a game+ Probability of losing a game=1

We are given that the probability of winning a game is 0.38.

Now we will put the probability to obtain the value,

0.38+Probability of losing a game=1

Probability of losing a game=1-0.38

Probability of losing a game=0.62

It can also be written as 62/100 which means that out of 100 games, the person will lose 62 of them.

Therefore, the probability of losing the game is 0.62.