If the probable error in single observation is plus or minus 0.04m and that of the mean is plus or minus 0.01m the the number of observations are
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Em=+-0.06745√(£v^2÷(n(n-1))=Es/√n Where :- Em =probable error of the mean. Es =probable error of single observation, n =no. Of observations. n=(0.04)^2÷(0.01)^2= 16. N=16.
The number of observations are meets the photograph with equal to declination of star plus.
If mistakes have been found, the results are great and probable error of single observation.
Answered by
31
Hey dear,
◆ Answer-
n = 16
◆ Explaination-
Probable error in single observation is
2SD = 0.04 m
SD = 0.02 m
Probable error in given sample is
2SEM = 0.01 m
SEM = 0.005 m
To calculate standard error of mean (SEM), we have formula
SEM = SD / √n
n = (SD/SEM)^2
n = (0.02/0.005)
n = 4^2
n = 16
Total number of observations in given sample is 16.
Hope this helps...
◆ Answer-
n = 16
◆ Explaination-
Probable error in single observation is
2SD = 0.04 m
SD = 0.02 m
Probable error in given sample is
2SEM = 0.01 m
SEM = 0.005 m
To calculate standard error of mean (SEM), we have formula
SEM = SD / √n
n = (SD/SEM)^2
n = (0.02/0.005)
n = 4^2
n = 16
Total number of observations in given sample is 16.
Hope this helps...
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