Question

If the product of 2 consecutive positive even integers is 168 find the integers

Answer 1

Heya !!!

This is Your Answer ...

Given :- Product of two consecutive even positive integers is 168.

Solution :- Let the first number be x.
The other number will be x+2.

Now, ATQ..
x (x+2) = 168
x² + 2x = 168 
x² + 2x - 168 = 0.

We have to find two nos. such that ab = -168 and a+b = 2.

By Looking at the Prime Factors of 168 ..
168 = 2 X 2 X 2 X 3 X 7.
So, we clearly get a and b as 2 X 2 X 3 = 12 and 7 X 2 = 14.

Now, ..........
x² + 2x - 168 = 0
x² + 14x - 12x - 168 = 0
x (x+14) - 12(x + 14) = 0
(x - 12) (x + 14) = 0
Comparing with 0, 
x = 12 and -14.
But, -14 is not a whole number.
So, x = 12, and
second number = x + 2
= 14.

Hope It Helps

Answer 2

Answer:

Step-by-step explanation: