Question

If the product of 2 positive consecutive even integers is 288, find the integers.​

Answer 1

using algebra...

n and n+2 are the integers

n*(n+2)=288

n^2+2n=288

n^2+2n-288=0

288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2

factor

(n+18)(n-16)=0

n+18=0

n=-18

n+2=-16

this is one solution

n-16=0

n=16

n+2=18