If the product of HCF and LCM of two natural numbers is 378000, then which of the following can be their HCF?
66,130,34,20.
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Heya user !!!
Here's the answer you are looking for
Let HCF = h and LCM = l
So, h × l = 378000
h × l / h = l which must be a whole number.
So, divide each option of h, where you get a whole number, that is the answer.
Here it goes .....
(a) 66
378000/66 = 5,727.27273 which is not a whole number.
So, 66 is not the answer.
(b) 130
378000/130 = 2,907.69231 which is not a whole number.
So, 130 is not the answer.
(c) 34
378000/34 = 11,117.6471 which is not a whole number.
So, 34 is not the answer.
(d) 20
378000/20 = 18,900 which is a whole number.
So, 20 is the answer.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let HCF = h and LCM = l
So, h × l = 378000
h × l / h = l which must be a whole number.
So, divide each option of h, where you get a whole number, that is the answer.
Here it goes .....
(a) 66
378000/66 = 5,727.27273 which is not a whole number.
So, 66 is not the answer.
(b) 130
378000/130 = 2,907.69231 which is not a whole number.
So, 130 is not the answer.
(c) 34
378000/34 = 11,117.6471 which is not a whole number.
So, 34 is not the answer.
(d) 20
378000/20 = 18,900 which is a whole number.
So, 20 is the answer.
★★ HOPE THAT HELPS ☺️ ★★
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