Question

if the product of nithin's age 6 yeats ago and 6 years hence is numerically equal to 64.then find the oresent age of nithin​

Answer 1

Answer:

Step-by-step explanation:

the product of Nitin's age 6 years ago and 6 years from now is equal to 64:

let Nitin's present age be 'x'

(x+6)(x-6)=64

x^2-(6)^2 = 64           [(a+b)(a-b) = a^2 - b^2]

x^2 = 64-36

x^2 = 28

x = $\sqrt{28}$

x = 2$\sqrt{7}$