Question

If the product of the 4th, 5th and 6th terms of a geometric progression is 4096 and if
the product of the 5th, 6th and 7th-terms of it is 32768, find the sum of first 8 terms of the geometric
progression

please answer this question
fast please by step by step
please answer​

Answer 1

Answer:

General term =arn−1

where, n=nth term

             r=common ratio

             a=first term

Now, ar3=10..............(1).ar6=80............(2)arn−1=2560.................(3)

Dividing (2) by (1)

r3=8⇒r=2

in (1)

a×8=10⇒a=810

in (3)

810×2n−1=2560⇒2n−1=256⇒2n−1=28⇒n−1=8⇒n=9

Answer 2

Answer:

sry I can't understand properly