Question

If the product of the numbers (n-1) and (n+1) is 999999 then find n​

Answer 1

${\bigstar}</p><p></p><p>\underline{\underline{\textsf{\textbf{Question \::- }}}}$

If the product of the numbers (n-1) and (n+1) is 999999 then find n

${\bigstar}</p><p></p><p>\underline{\underline{\textsf{\textbf{ Solution\::- }}}}$

$(n - 1) \: (n + 1) = 999999$

${n}^{2} + n - n - 1 = 999999$

${n}^{2} + 2 - 1 = 999999$

${n}^{2} = 999999 - 1$

${n}^{2} = 999998$

$n = \sqrt {999998}$

$\therefore \: n = 999.99$