Question

If the product of the roots of the equation (a + 1)x2 + (2a + 3)x + (3a + 4) = 0 be 2, then the sum of roots​

Answer 1

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$(a + 1)x {}^{2} + (2a + 3)x + (3a + 4) = 0 \\ = > x {}^{2} + \frac{(2a + 3)}{(a + 1)} x + \frac{(3a + 4)}{(a + 1)} = 0 \\ = the \: product \: of \: the \: equation \: is \: 2 \\ therefore ........\\ = > \frac{(3a + 4)}{(a + 1)} = 2 \\ = > 3a + 4 = 2a + 2 \\ = > a = - 2 \\ \\ now \: the \: sum \: of \: the \: equation \: is \: \: \: \\ = \frac{-(2a + 3)}{(a + 1)} \\ = -\frac{2( - 2) + 3}{ - 2 + 1} \\ = -\frac{ - 4 + 3}{ - 1} \\ = -\frac{ - 1}{ - 1} \\ = -1$

the sum of roots of the equation is =-1

$\underline{\large\mathcal\red{hope\: this \: helps \:you......}}$