if the product of the roots of the equation mx^2-2x+2m-1=0 is 3 then the value of m is
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For the equation to possess no real roots,
Its discriminant must be <0
=> b^2 - 4ac < 0
=> (m+1)^2 - 4(m)(2m+1) <0
=> m^2+1+2m - 8m^2–4m < 0
=> -7m^2 -2m+1 < 0
Since, the leading coefficient < 0, Therefore the value of the expression would be less than 0 for all values of m, except the ones in between the zeros.
Here,
D = 4 - 4(1)(-7) = 4+28 = 32 = 4 √2,
Therefore, Zeroes =( 2 + 4 √2)/-14 and (2- 4 √2)-14
Hence, The equation would possess no real roots for all real values of m, except those between ( 2 + 4 √2)/-14 and (2- 4 √2)-14
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