Question

If the product of the zeroes of a polynomial 3x2 - 8x + 3k is
12 the value of k is​

Answer 1

Answer:

3x2-8x+2k+1 a=3, b=-8,c=2k+1

suppose the zeroes of the equation are a and B by the given condition a=7B

as we know, a+B=-b/a

7B+B=-(-8)/3 8B=8/3

B=8/3x1/8=1/3

aß=c/a

7BXB=2k+1/3

7x1/3x1/3=2k+1/3 7/9=2k+1/3

21/9=2k+1

21/9-1=2k

12/9=2k

4/3=2k

4/6=k

2/3=k