If the product of the zeroes of the polynomial kx is 4, then the value of k is
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Appropriate question :
If the product of the zeroes of the polynomial kx² - 6x - 6 is 4, then find the value of k.
Solution :
We know that :
- Product of zeroes (αβ) = c/a
When we compare kx² - 6x - 6 to ax² + bx + c, we get :
- a = k
- b = -6
- c = -6
Now, substituting :
- c/a = 4
- -6/k = 4
- -6 = 4k
- k = -6/4
- k = -3/2
Therefore, k = -3/2 when 4 is the product of the zeroes of the polynomial kx² - 6x - 6.
Know more :
- Sum of the zeroes (α+β) = -b/a
- Product of the zeroes (αβγ) = -d/a
- Sum of the zeroes (α+β+γ) = -b/a
- Sum of the zeroes (αβ + βγ + γα) = c/a
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