Question

If the product of the zeroes of the polynomial (m + 1)x^2 + (2m + 3)x + (3m +4) is 2, find the
sum of its zeroes.​

Answer 1

You can see the answer in adjoining pic.

Hope it helps...

Answer 2

Given:

Product of the polynomial p(x) = (m + 1)x² + (2m + 3)x + (3m + 4) = 0 is 2

To find:

Sum of its zeroes.

Solution:

Product of zeroes = c/a

=> 2 = (3m + 4)/(m + 1)

=> 2m + 2 = 3m + 4

=> m = -2

Sum of zeroes = -b/a

=> -(2m + 3)/(m + 1)

Put value of m. m = -2

=> -(-4 + 3)/(-2 + 1)

=> -(-1)/(-1)

=> -1

Answer is -1