Question

if the product of the zeroes of the polynomial Mx²- 6x - 6 is -3 then find value of m.​

Answer 1

Answer:

$m {x}^{2} - 6x - 6 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: (x - 3) \\ now \: x - 3 = 0 \: \: \: \: x = 3 \: \: we \: will \: put \: the \: value \:in \: the \: equation \\ m( {3}^{2} ) - 6 \times 3 - 6 = 0 \\ 9m - 18 - 6 = 0 \\ 9m - 24 = 0 \\ 9m = 24 \\ m = \frac{24}{9} = 2.666667$

Step-by-step explanation:

this is ur answer

Answer 2

Answer:

M = 2

Step-by-step explanation:

Given: Mx²- 6x - 6

$\alpha \beta = - 3 > > product \: of \: the \: zeroes$

$\alpha \beta = \frac{c}{a}$

FROM THE STANDARD FORMULA OF QUADRATIC POLYNOMIAL

$a {x}^{2} + bx \: + c = 0$

So from the given we can solve M:

$\alpha \beta = \frac{c}{a}$

Substitute all the given to the formula shown above.

$\alpha \beta = \frac{c}{a} \\ \\ - 3 = \frac{ - 6}{M} \\ \\ - 3M = - 6 \\ \\ \frac{ - 3M}{ - 3} = \frac{ - 6}{ - 3} \\ \\ M = 2$