Question

If the Product of the zeroes of the quadratic polynomial 2x²-9k=0 is 6, then find the value of k.​

Answer 1

Answer:

$\ \\ a = 2 \: \: \: \: \: b = 0 \: \: \: \: c = - 9k \\ \alpha \times \beta = \frac{c}{a} \\ 6 = \frac{ - 9k}{2} \\ 12 = - 9k \\ k = \frac{12}{ - 9 } \\ k = \frac{ - 4}{3}$