Question

If the product of the zeroes of the quadratic
polynomial
3x^2 - 6x + k is 3, then find the value of k.​

Answer 1

Answer:

the value of k is 9.... the product of roots is c÷a

Answer 2

Answer:

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Step-by-step explanation:

ANSWER

In a general quadratic equation of form ax2+bx+c=0, sum of roots are by -b/a

.In the given quadratic equation, 3x²−kx+6=0

a=3,b=−k,c=6

Sum of roots = - b/a

= −(−k) / 3

= k/3

and sum of roots is given 3

⇒ k/3 =3

⇒ k=9