Question

If the product of the zeroes of the quadratic polynomial nx² +6x+(2n-1) is -1, then find the value of n.​

Answer 1

Given polynomial:- ax2−6x−6

a=a,b=−6,c=−6

Product of zeroes =4(Given)

As we know that, for a quadratic polynomial-

Product of zeroes =ac

∴ac=4

⇒a−6=4⇒a=4−6=2−3

Hence, this is the answer.

Answer 2

Given:-

Quadratic polynomial = $nx^{2} + 6x+(2n-1)$

Product of Quadratic polynomial  $nx^{2} + 6x+(2n-1)$ = -1

Find out:- Value of n

According to the question;

product of Zeroes = $\frac{2n-1}{n}$

Now,

$\frac{(2n - 1)}{n} = -1\\2n-1=-n\\2n+n-1=0\\3n=1\\n= \frac{1}{3}$

Answer:-

If the product of the zeroes of the quadratic polynomial  $nx^{2} + 6x+(2n-1)$  is -1, then the value of n is $\frac{1}{3}$.

Learn More:-

1. zeros of the quadratic polynomial:- https://brainly.in/question/4030571

2. Verify the relation between the coefficients and zeros of the polynomial:- https://brainly.in/question/2419050

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