Question

if the product of the zeroes of x square - 3kx + 2k square - 1 is 7. then value of k are :​

Answer 1

Answer:

✅Here's your answer

$\alpha \beta = \frac{c}{a} \ \\ 2 {k}^{2} - 3kx + 2k - 1 \\ \\ \alpha \beta = \frac{ - 1}{2k} \\ 7 \times 2k = - 1 \\ 14k = - 1 \\ k = \frac{ - 1}{14}$

Hope it helps ✌

Answer 2

The value of k is $\pm 2$.

Step-by-step explanation:

Given : If the product of the zeroes of $x^2-3kx+2k^2-1$ is 7.

To find : The value of k ?

Solution :

We know the product of zeros of quadratic equation $ax^2+bx+c$ is given by,

$\alpha \beta =\frac{c}{a}$

If the product of the zeroes of $x^2-3kx+2k^2-1$ is 7.

Here, a=1, b=-3k , $c=2k^2-1$ and $\alpha \beta =7$

Substitute in the formula,

$7=\frac{2k^2-1}{1}$

$2k^2-1=7$

$2k^2=8$

$k^2=4$

$k=\pm 2$

Therefore, the value of k is $\pm 2$.

#Learn more

Sum of zeroes and product of zeros ​

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