Math, asked by smarttejas548, 10 months ago

If the product of the zeroes of x² - 3kx + 2k1 - 1 is 7, then values of k are ________ and ______
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mysticd: Is it 2k-1 or 2k1-1
mysticd: what is the last term is it 2k²-1

Answers

Answered by mysticd
3

/* It may like this */

 Compare \:the \: polynomial\\ x^{2}-3kx+2k^{2}-1 \:with \:ax^{2} + bx + c, we \:get

 a = 1 , \: b = -3k , \: c = 2k^{2} - 1

 Now, Product \: of \: zeroes = 7 \:(given)

 \implies \frac{c}{a} = 7

 \implies \frac{2k^{2} - 1}{1} = 7

 \implies 2k^{2} = 7 + 1

 \implies 2k^{2} = 8

 \implies k^{2} = \frac{8}{2}

 \implies k^{2} = 4

 \implies k = \pm {2^{2}}

 \implies k = \pm 2

Therefore.,

 \green { Values \: of \: k \:are \:-2 \:and \: 2 }

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Answered by rajparekh18
0

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k = +2

k = -2

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