Question

If the product of the zeros of of the polyamial
(ax^2- 6x-6) is 4, find the value of a​

Answer 1

Answer:

p(x)=ax²-6x-6

x=4 ..........(given)

p(4)=a(4)²-6(2)-6=0.........(b/z x=4 is zero of p(x))

=> 16a-12-6=0

=> 16a-18=0

=> 16a=18

=> a=9/8

hope it helps you....✌✌