if the product of the zeros of the polynomial ax square - 6 x minus 6 is 4 then find the value of a
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ax^2 -6x - 6 = 0
Given that product of zeroes = 4
Also product of zeroes = constant value / coefficient of x^2
= -6/a
so
-6/a = 4
a = -6/4
a = -3/2
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