Question

If the product of the zeros of the polynomial (ax2 -6x +8) is 4, find the value of a

Answer 1

Answer

The required value of a is 2

Given

The quadratic polynomial is :

• ax² - 6x + 8
• The product of the zeroes is 4

To Find

• The value of a

Solution

We know that

$\sf Product \: of \: the \: zeroes =\dfrac{ Constant \: term }{ Coefficient \: of \: x^{2} } \\\\ \sf\implies 4 = \dfrac{8}{a} \\\\ \sf\implies 4a = 8 \\\\ \sf\implies a = 2$

Thus , the value of a is 2

Also the quadratic polynomial obtained is :

2x² - 6x + 8